我有以下 JSON 结构：
[{ "id":"10", "class": "child-of-9" }, { "id": "11", "classd": "child-of-10" }]
如何使用 JavaScript 迭代它？
如何迭代 JSON 结构？
IT技术
javascript
json
loops
2021-02-04 16:32:28
6个回答
var arr = [ {"id":"10", "class": "child-of-9"}, {"id":"11", "class": "child-of-10"}];
for (var i = 0; i < arr.length; i++){
document.write("<br><br>array index: " + i);
var obj = arr[i];
for (var key in obj){
var value = obj[key];
document.write("<br> - " + key + ": " + value);
}
}注意：for-in 方法对于简单的对象很酷。与 DOM 对象一起使用不是很聪明。
取自jQuery 文档：
var arr = [ "one", "two", "three", "four", "five" ];
var obj = { one:1, two:2, three:3, four:4, five:5 };
jQuery.each(arr, function() {
$("#" + this).text("My id is " + this + ".");
return (this != "four"); // will stop running to skip "five"
});
jQuery.each(obj, function(i, val) {
$("#" + i).append(document.createTextNode(" - " + val));
});
使用的...的：
var mycars = [{name:'Susita'}, {name:'BMW'}];
for (var car of mycars)
{
document.write(car.name + "<br />");
}结果：
Susita
BMW
如果这不容易，请告诉我：
var jsonObject = {
name: 'Amit Kumar',
Age: '27'
};
for (var prop in jsonObject) {
alert("Key:" + prop);
alert("Value:" + jsonObject[prop]);
}
如果这是您的dataArray：
var dataArray = [{"id":28,"class":"Sweden"}, {"id":56,"class":"USA"}, {"id":89,"class":"England"}];
然后：
$(jQuery.parseJSON(JSON.stringify(dataArray))).each(function() {
var ID = this.id;
var CLASS = this.class;
});