我试图对发送一些文本并附加特定数字的协议进行逆向工程。我发现该数字是某种校验和（以某种方式取决于文本），并且在诸如“aaaaaaab”= X 和“aaaaaaba”= X+1 的情况下它会增加 1。这里有人知道我可以处理什么吗？

附加数据：

iiiiiiii =  4d0b 
iiiiiiil =  920b 
iiiiiill =  ce0b 
iiiiilll =  120c 
iiiillll =  5a0c 
iiilllll =  990c 
iillllll =  dd0c 
illlllll =  210d 
llllllll =  680d
liiiiiii =  940b 
iliiiiii =  950b 
iiliiiii =  960b 
iiiliiii =  970b 
iiiiliii =  980b 
iiiiilii =  990b 
iiiiiili =  9b0b 
iiiiiiil =  920b 
aaaaaaaa =  210f 
aaaaaaab =  a110 
aaaaaaba =  a210 
aaaaaaca =  9f0f 
aaaaaacb =  1f11 
baaaaaaa =  a610 

第二部分是我推断的取决于字符串的数字。从数据中也很明显，前两位数字是最不重要的。