我在 TypeScript 中使用 React.js。有没有办法创建继承自其他组件但有一些额外props/状态的 React 组件?
我想要实现的是这样的:
interface BaseStates {
    a: number;
}
class GenericBase<S extends BaseStates> extends React.Component<void, S> {
    protected getBaseInitialState(): BaseStates {
        return { a: 3 };
    }
}
class Base extends GenericBase<BaseStates> {
    getInitialState(): BaseStates {
        return super.getBaseInitialState();
    }
}
interface DerivedStates extends BaseStates {
    b: number;
}
class Derived extends GenericBase<DerivedStates> {
    getInitialState(): DerivedStates {
        var initialStates = super.getBaseInitialState() as DerivedStates; // unsafe??
        initialStates.b = 4;
        return initialStates
    }
}
但是,如果我把这个会失败this.setState中Derived,我得到一个错误的typescript(类型的参数DerivedStates是不能分配给类型S)。我想这不是 TypeScript 特定的东西,而是将继承与泛型 (?) 混合使用的一般限制。是否有任何类型安全的解决方法?
更新
我确定的解决方案(基于 David Sherret 的回答):
interface BaseStates {
    a: number;
}
class GenericBase<S extends BaseStates> extends React.Component<void, S> {
    constructor() {
        super();
        this.state = this.getInitialState();
    }
    getInitialState(): S {
        return { a: 3 } as S;
    }
    update() {
        this.setState({ a: 7 } as S);
    }
}
interface DerivedStates extends BaseStates {
    b: number;
}
class Derived extends GenericBase<DerivedStates> {
    getInitialState(): DerivedStates {
        var initialStates = super.getInitialState();
        initialStates.b = 4;
        return initialStates;
    }
    update() {
        this.setState({ a: 7, b: 4 });
    }
}