我有一个<UserListComponent />输出一个<Contact />组件和由<Contacts />.
问题是在<UserListComponent />我尝试挂载时的测试中,测试输出错误Invariant Violation: You should not use <Route> or withRouter() outside a <Router>
withRouter()在<Contacts />组件中使用。
如何ContactsComponent在没有路由器的情况下模拟父组件?
我发现了一些类似的问题https://www.bountysource.com/issues/49297944-invariant-violation-you-should-not-use-route-or-withrouter-outside-a-router
但它只描述了组件的情况单独覆盖withRouter(),而不是儿童。
用户列表.test.jsx
const mockResp = {
  count: 2,
  items: [
    {
      _id: 1,
      name: 'User1',
      email: 'email1@gmail.com',
      phone: '+123456',
      online: false
    },
    {
      _id: 2,
      name: 'User2',
      email: 'email2@gmail.com',
      phone: '+789123',
      online: false
    },
    {
      _id: 3,
      name: 'User3',
      email: 'email3@gmail.com',
      phone: '+258369147',
      online: false
    }
  ],
  next: null
}
describe('UserList', () => {
  beforeEach(() => {
    fetch.resetMocks()
  });
  test('should output list of users', () => {
    fetch.mockResponseOnce(JSON.stringify(mockResp));
    const wrapper = mount(<UserListComponent user={mockResp.items[2]} />);
    expect(wrapper.find('.contact_small')).to.have.length(3);
  });
})
用户列表.jsx
export class UserListComponent extends PureComponent {
  render() {
    const { users, error } = this.state;
    return (
      <React.Fragment>
        <Contact
          userName={this.props.user.name}
          content={this.props.user.phone}
        />
        {error ? <p>{error.message}</p> : <Contacts type="contactList" user={this.props.user} contacts={users} />}
      </React.Fragment>
    );
  }
}
联系人.jsx
class ContactsComponent extends Component {
  constructor() {
    super();
    this.state = {
      error: null,
    };
  }
  render() {
    return (
      <React.Fragment>
        <SectionTitle title="Contacts" />
        <div className="contacts">
         //contacts
        </div>
      </React.Fragment>
    );
  }
}
export const Contacts = withRouter(ContactsComponent);